QUESTION
A Solution contains 25% water, 25% ethanol and 50% acetic acid by mass. Calculate the mole fraction of each compound?
ANSWER
If we have 100 g of solution,
Mass of Water = 25 g Molecular mass of water=18g
Mass of Ethanol= 25g Molecular mass of Ethanol=46g
Mass of Acetic acid=50g Molecular mass of Acetic acid= 60g
No of moles of water 25/18 = 1.39
No of moles of Ethanol= 25/46 = 0.54
No of moles of Acetic acid = 0.83
Total no of moles = 1.39+0.54+0.83 = 2.76
Mole fraction of water =1.39/2.76 =0.503
Mole fraction of ethanol = 0.54/2.76=0.196
Mole fraction of acetic acid =0.83/2.76= 0.301
